Hackerrank Array Mathematics Solution
Poor Man
- Published
- Updated
- Reading time
- 3 min read
- Length
- 474 words
Basic mathematical functions operate element-wise on arrays. They are available both as operator overloads and as functions in the NumPy module.
Text
import numpy
a = numpy.array([1,2,3,4], float)
b = numpy.array([5,6,7,8], float)
print a + b #[ 6. 8. 10. 12.]
print numpy.add(a, b) #[ 6. 8. 10. 12.]
print a - b #[-4. -4. -4. -4.]
print numpy.subtract(a, b) #[-4. -4. -4. -4.]
print a * b #[ 5. 12. 21. 32.]
print numpy.multiply(a, b) #[ 5. 12. 21. 32.]
print a / b #[ 0.2 0.33333333 0.42857143 0.5 ]
print numpy.divide(a, b) #[ 0.2 0.33333333 0.42857143 0.5 ]
print a % b #[ 1. 2. 3. 4.]
print numpy.mod(a, b) #[ 1. 2. 3. 4.]
print a**b #[ 1.00000000e+00 6.40000000e+01 2.18700000e+03 6.55360000e+04]
print numpy.power(a, b) #[ 1.00000000e+00 6.40000000e+01 2.18700000e+03 6.55360000e+04]Task
You are given two integer arrays, and of dimensions X.
Your task is to perform the following operations:
- Add ( + )
- Subtract ( - )
- Multiply ( * )
- Integer Division ( / )
- Mod ( % )
- Power ( ** )
Input Format
The first line contains two space separated integers, and .
The next lines contains space separated integers of array .
The following lines contains space separated integers of array .
Output Format
Print the result of each operation in the given order under Task.
Sample Input
Text
1 4
1 2 3 4
5 6 7 8Sample Output
Text
[[ 6 8 10 12]]
[[-4 -4 -4 -4]]
[[ 5 12 21 32]]
[[0 0 0 0]]
[[1 2 3 4]]
[[ 1 64 2187 65536]] Use // for division in Python 3.
Solution in python3#
Approach 1.
Python
import numpy
n,m = map(int,input().split())
a = numpy.array([input().split() for _ in range(n)],int)
b = numpy.array([input().split() for _ in range(n)],int)
print(a+b,a-b,a*b,a//b,a%b,a**b,sep="\n")Approach 2.
Python
import numpy
n,m=map(int,input().split())
A=numpy.array([list(map(int,input().split())) for i in range(n)])
B=numpy.array([list(map(int,input().split())) for i in range(n)])
print(A+B,A-B,A*B,A//B,A%B,A**B,sep='\n')Approach 3.
Python
from numpy import *
n,m = map(int,input().split())
a = array([[int(x) for x in input().split()] for _ in range(n)],int)
b = array([[int(x) for x in input().split()] for _ in range(n)],int)
print(a+b,a-b,a*b,a//b,a%b,a**b,sep = '\n')Solution in python#
Python
import numpy
N, M= map(int, raw_input().split())
A = numpy.array([map(int, raw_input().split()) for i in range(N)])
B = numpy.array([map(int, raw_input().split()) for i in range(N)])
print A+B
print A-B
print A*B
print A / B
print A % B
print A**B
