Hackerrank OrderedDict solution

_{collections.OrderedDict}

An OrderedDict is a dictionary that remembers the order of the keys that were inserted first. If a new entry overwrites an existing entry, the original insertion position is left unchanged.

Example

_Code

>>> from collections import OrderedDict
>>> 
>>> ordinary_dictionary = {}
>>> ordinary_dictionary['a'] = 1
>>> ordinary_dictionary['b'] = 2
>>> ordinary_dictionary['c'] = 3
>>> ordinary_dictionary['d'] = 4
>>> ordinary_dictionary['e'] = 5
>>> 
>>> print ordinary_dictionary
{'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4}
>>> 
>>> ordered_dictionary = OrderedDict()
>>> ordered_dictionary['a'] = 1
>>> ordered_dictionary['b'] = 2
>>> ordered_dictionary['c'] = 3
>>> ordered_dictionary['d'] = 4
>>> ordered_dictionary['e'] = 5
>>> 
>>> print ordered_dictionary
OrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4), ('e', 5)])

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Task

You are the manager of a supermarket.
You have a list of  items together with their prices that consumers bought on a particular day.
Your task is to print each item_name and net_price in order of its first occurrence.

_{item_name = Name of the item.
net_price = Quantity of the item sold multiplied by the price of each item.}

Input Format

The first line contains the number of items, .
The next  lines contains the item's name and price, separated by a space.

Constraints

Output Format

Print the item_name and net_price in order of its first occurrence.

Sample Input

9
BANANA FRIES 12
POTATO CHIPS 30
APPLE JUICE 10
CANDY 5
APPLE JUICE 10
CANDY 5
CANDY 5
CANDY 5
POTATO CHIPS 30

Sample Output

BANANA FRIES 12
POTATO CHIPS 60
APPLE JUICE 20
CANDY 20

Explanation

BANANA FRIES: Quantity bought: , Price:
Net Price:
POTATO CHIPS: Quantity bought: , Price:
Net Price:
APPLE JUICE: Quantity bought: , Price:
Net Price:
CANDY: Quantity bought: , Price:
Net Price:

Solution in Python

from collections import OrderedDict
d = OrderedDict()
for i in range(int(input())):
    name,blank,price = input().rpartition(" ") 
    d[name]= d.get(name,0)+int(price)
for i in d.items():
    print(*i)

We can also use Counter

from collections import Counter
d = Counter()
for i in range(int(input())):
    name,blank,price = input().rpartition(" ") 
    d[name]= d[name]+int(price)
for i in d.items():
    print(*i)