Hackerrank Strings Solution
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- Updated
- Reading time
- 2 min read
- Length
- 328 words
C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:
Declaration:
string a = "abc";Size:
int len = a.size();Concatenate two strings:
string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".Accessing element:
string s = "abc";
char c0 = s[0]; // c0 = 'a'
char c1 = s[1]; // c1 = 'b'
char c2 = s[2]; // c2 = 'c'
s[0] = 'z'; // s = "zbc"P.S.: We will use cin/cout to read/write a string.
Input Format
You are given two strings, and , separated by a new line. Each string will consist of lower case Latin characters ('a'-'z').
Output Format
In the first line print two space-separated integers, representing the length of and respectively.
In the second line print the string produced by concatenating and ().
In the third line print two strings separated by a space, and . and are the same as and , respectively, except that their first characters are swapped.
Sample Input
abcd
efSample Output
4 2
abcdef
ebcd afExplanation
- "abcd"
- "ef"
- "abcdef"
- "ebcd"
- "af"
Solution in cpp#
Approach 1.
#include <iostream>
#include <string>
using namespace std;
int main() {
string a,b;
char temp;
cin>>a>>b;
cout<<a.size()<<' '<<b.size()<<endl;
cout<<a+b<<endl;
temp=a[0];
a[0]=b[0];
b[0]=temp;
cout<<a<<' '<<b;
return 0;
}Approach 2.
#include <iostream>
#include <string>
using namespace std;
int main() {
string a,b;
char i,j;
int c,d;
cin>>a;
cin>>b;
c=a.size();
d=b.size();
cout<<c<<" "<<d<<"\n";
cout<<a+b<<"\n";
i=b[0];
b[0]=a[0];
a[0]=i;
cout<<a<<" ";
cout<<b;
return 0;
}
Approach 3.
#include <iostream>
#include <string>
using namespace std;
int main() {
std::string a, b;
std::cin >> a >> b;
std::cout << a.size() << " " << b.size() << std::endl
<< a + b << std::endl;
std::swap(a[0], b[0]);
std::cout << a << " " << b;
return 0;
}
