Leetcode - Best Time to Buy and Sell Stock II Solution
Poor Man
- Published
- Updated
- Reading time
- 2 min read
- Length
- 260 words
You are given an array prices where prices[i] is the price of a given stock on the ith day.
Find the maximum profit you can achieve. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).
Note: You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).
Example 1:
Text
Input: prices = [7,1,5,3,6,4]
Output: 7
Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.
Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.Example 2:
Text
Input: prices = [1,2,3,4,5]
Output: 4
Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are engaging multiple transactions at the same time. You must sell before buying again.Example 3:
Text
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transaction is done, i.e., max profit = 0.Constraints:
1 <= prices.length <= 3 * 1040 <= prices[i] <= 104
Solution in python #
Python
class Solution:
def maxProfit(self, prices: List[int]) -> int:
down = prices[0]
i = 0
profit = 0
while True:
while i<len(prices) and prices[i]>down:
profit += prices[i]-down
down = prices[i]
i+=1
else:
if i==len(prices):
break
down = prices[i]
i += 1
return profit