Leetcode - Count of Matches in Tournament Solution
Poor Man
- Published
- Updated
- Reading time
- 2 min read
- Length
- 248 words
You are given an integer n, the number of teams in a tournament that has strange rules:
- If the current number of teams is even, each team gets paired with another team. A total of
n / 2matches are played, andn / 2teams advance to the next round. - If the current number of teams is odd, one team randomly advances in the tournament, and the rest gets paired. A total of
(n - 1) / 2matches are played, and(n - 1) / 2 + 1teams advance to the next round.
Return the number of matches played in the tournament until a winner is decided.
Example 1:
Text
Input: n = 7
Output: 6
Explanation: Details of the tournament:
- 1st Round: Teams = 7, Matches = 3, and 4 teams advance.
- 2nd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 3 + 2 + 1 = 6.Example 2:
Text
Input: n = 14
Output: 13
Explanation: Details of the tournament:
- 1st Round: Teams = 14, Matches = 7, and 7 teams advance.
- 2nd Round: Teams = 7, Matches = 3, and 4 teams advance.
- 3rd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 7 + 3 + 2 + 1 = 13.Constraints:
1 <= n <= 200
Solution in Python#
Python
class Solution:
def numberOfMatches(self, n: int) -> int:
matches = 0
while n>1:
matches+=n//2
n-=n//2
return matches