Leetcode - Power of Three Solution

Given an integer n, return true if it is a power of three. Otherwise, return false.

An integer n is a power of three, if there exists an integer x such that n == 3x.

Example 1:

Input: n = 27
Output: true

Example 2:

Input: n = 0
Output: false

Example 3:

Input: n = 9
Output: true

Example 4:

Input: n = 45
Output: false

Constraints:

  • -231 <= n <= 231 - 1

Follow up: Could you solve it without loops/recursion?

Solution in python

class Solution:
    def isPowerOfThree(self, n: int) -> bool:
        if n <= 0:
            return False
        return (math.log10(n) / math.log10(3))%1 == 0

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