Leetcode - Reverse Integer Solution
Poor Man
- Published
- Updated
- Reading time
- 1 min read
- Length
- 119 words
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Text
Input: x = 123
Output: 321Example 2:
Text
Input: x = -123
Output: -321Example 3:
Text
Input: x = 120
Output: 21Example 4:
Text
Input: x = 0
Output: 0Constraints:
-231 <= x <= 231 - 1
Solution in Python#
Python
class Solution:
def reverse(self, x: int) -> int:
if x<0:
x = int(str(x*-1)[::-1])*-1
else:
x = int(str(x)[::-1])
if x >= -2**31 and x <= 2**31-1:
return x
else:
return 0